2y^2+50y^2=0

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Solution for 2y^2+50y^2=0 equation: 



2y^2+50y^2=0

We add all the numbers together, and all the variables

52y^2=0

a = 52; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·52·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{104}=0$

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